[sprout.functional] add all transparent functors

This commit is contained in:
bolero-MURAKAMI 2013-10-26 23:17:09 +09:00
parent 2a57ee6af5
commit be9a5f9b78
59 changed files with 1047 additions and 301 deletions

View file

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/*=============================================================================
Copyright (c) 2011-2013 Bolero MURAKAMI
https://github.com/bolero-MURAKAMI/Sprout
Distributed under the Boost Software License, Version 1.0. (See accompanying
file LICENSE_1_0.txt or copy at http://www.boost.org/LICENSE_1_0.txt)
=============================================================================*/
#ifndef SPROUT_FUNCTIONAL_CALL_FUN_HPP
#define SPROUT_FUNCTIONAL_CALL_FUN_HPP
#include <utility>
#include <sprout/config.hpp>
#include <sprout/utility/forward.hpp>
namespace sprout {
//
// call_fun
//
template<typename T = void>
struct call_fun;
template<>
struct call_fun<void> {
public:
typedef void is_transparent;
public:
template<typename F, typename... As>
SPROUT_CONSTEXPR decltype(std::declval<F>()(std::declval<As>()...))
operator()(F&& f, As&&... as)
const SPROUT_NOEXCEPT_EXPR(SPROUT_NOEXCEPT_EXPR(std::declval<F>()(std::declval<As>()...)))
{
return sprout::forward<F>(f)(sprout::forward<As>(as)...);
}
};
} // namespace sprout
#endif // #ifndef SPROUT_FUNCTIONAL_CALL_FUN_HPP