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86 lines
4 KiB
ReStructuredText
86 lines
4 KiB
ReStructuredText
.. _sprout-algorithm-tristate_lexicographical_compare:
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###############################################################################
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tristate_lexicographical_compare
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###############################################################################
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Interface
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========================================
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.. sourcecode:: c++
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template<typename InputIterator1, typename InputIterator2>
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inline SPROUT_CONSTEXPR int
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tristate_lexicographical_compare(
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InputIterator1 first1, InputIterator1 last1,
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InputIterator2 first2, InputIterator2 last2
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);
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template<typename InputIterator1, typename InputIterator2, typename Compare>
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inline SPROUT_CONSTEXPR int
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tristate_lexicographical_compare(
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InputIterator1 first1, InputIterator1 last1,
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InputIterator2 first2, InputIterator2 last2,
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Compare comp
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);
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// delimiter version
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template<typename InputIterator1, typename T1, typename InputIterator2, typename T2>
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inline SPROUT_CONSTEXPR int
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tristate_lexicographical_compare(
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InputIterator1 first1, InputIterator1 last1, T1 const& delim1,
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InputIterator2 first2, InputIterator2 last2, T2 const& delim2
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);
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template<typename InputIterator1, typename T1, typename InputIterator2, typename T2, typename Compare>
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inline SPROUT_CONSTEXPR int
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tristate_lexicographical_compare(
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InputIterator1 first1, InputIterator1 last1, T1 const& delim1,
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InputIterator2 first2, InputIterator2 last2, T2 const& delim2,
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Compare comp
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);
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Returns
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========================================
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| A value less than zero if the sequence of elements defined by the range [first1,last1) is lexicographically less than the sequence of elements defined by the range [first2,last2).
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| Otherwise, a value greater than zero if the sequence of elements defined by the range [first1,last1) is lexicographically greater than the sequence of elements defined by the range [first2,last2).
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| Otherwise, returns a zero value.
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| If the delimiter version, last1 and last2 the following corresponding transformations: ``find_if(first1, last1, bind2nd(equiv(), delim1))`` and ``find_if(first2, last2, bind2nd(equiv(), delim1))``, ``find_if(first1, last1, bind2nd(equiv(comp), delim1))`` and ``find_if(first2, last2, bind2nd(equiv(comp), delim1))``.
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Remarks
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========================================
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| If two sequences have the same number of elements and their corresponding elements are equivalent, then neither sequence is lexicographically less than the other.
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| If one sequence is a prefix of the other, then the shorter sequence is lexicographically less than the longer sequence.
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| Otherwise, the lexicographical comparison of the sequences yields the same result as the comparison of the first corresponding pair of elements that are not equivalent.
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| An empty sequence is lexicographically less than any non-empty sequence, but not less than any empty sequence.
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Examples
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========================================
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.. sourcecode:: c++
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#include <sprout/algorithm/tristate_lexicographical_compare.hpp>
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#include <sprout/array.hpp>
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#include <sprout/container.hpp>
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using namespace sprout;
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SPROUT_STATIC_CONSTEXPR auto input1 = array<int, 10>{{1, 2, 3, 4, 5, 6, 7, 8, 9, 10}};
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SPROUT_STATIC_CONSTEXPR auto input2 = array<int, 10>{{1, 2, 3, 4, 5, 10, 9, 8, 7, 6}};
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SPROUT_STATIC_CONSTEXPR auto result1 = sprout::tristate_lexicographical_compare(begin(input1), end(input1), begin(input2), end(input2));
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SPROUT_STATIC_CONSTEXPR auto result2 = sprout::tristate_lexicographical_compare(begin(input1), end(input1), 10, begin(input2), end(input2), 10);
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static_assert(result1 < 0, "input1 < input2 by lexicographical comparison.");
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static_assert(result2 > 0, "input1 < input2 by lexicographical comparison(delimited by 10).");
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Complexity
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========================================
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| At most ``2*min((last1 - first1), (last2 - first2)) + O(1)`` applications of the corresponding comparison.
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| Recursive function invocations in *O(logN)* (logarithmic) depth.
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Header
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========================================
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| ``sprout/algorithm/tristate_lexicographical_compare.hpp``
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| Convenience header: ``sprout/algorithm.hpp``
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